(3c+5)^2-c(2c+3)=c+1

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Solution for (3c+5)^2-c(2c+3)=c+1 equation: 



(3c+5)^2-c(2c+3)=c+1

We move all terms to the left:

(3c+5)^2-c(2c+3)-(c+1)=0

We multiply parentheses

-2c^2+(3c+5)^2-3c-(c+1)=0

We get rid of parentheses

-2c^2+(3c+5)^2-3c-c-1=0

We add all the numbers together, and all the variables

-2c^2-4c+(3c+5)^2-1=0

We move all terms containing c to the left, all other terms to the right

-2c^2-4c+(3c+5)^2=1

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